Step 1: Idea:
The method needs a suitable alkyl halide that undergoes $\text{S}_\text{N}2$ with the phthalimide anion.
Step 2: Result:
Chlorobenzene would be needed for aniline, and it does not react. The other three halides are primary alkyl or benzyl halides, which react easily.
Final Answer:
Aniline is not obtained by this method, option (A).
\[ \boxed{\text{Aniline}} \]