When UV light of wavelength 300 nm is incident on the metal surface having work function 2.13 eV, electron emission takes place. The stopping potential is : (Given hc = 1240 eV nm)

Question

Light is incident on a metallic plate having work function \(110 \times 10^{-20}\,\text{J}\). If the produced photoelectrons have zero kinetic energy, then the angular frequency of the incident light is _________ rad/s. (\(h = 6.63 \times 10^{-34}\,\text{J·s}\))}

Answer 1

The incident photon energy, calculated as \[\frac{hc}{\lambda} = eV_s + \phi\], is substituted with the given values: \[\frac{1240}{300} \, \text{eV} - 2.13 \, \text{eV} = eV_s\]. This simplifies to \[4.13 \, \text{eV} - 2.13 \, \text{eV} = eV_s\], yielding a stopping potential of \[V_s = 2 \, \text{V}\].

When UV light of wavelength 300 nm is incident on the metal surface having work function 2.13 eV, electron emission takes place. The stopping potential is : (Given hc = 1240 eV nm)

The Correct Option is C

Solution and Explanation

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