Question

When two resistors are connected in the two gaps of a meter bridge, the balancing point is obtained at \(25\,\text{cm}\) from the left end of the bridge wire. When a \(48\,\Omega\) resistor is connected in series to the smaller of the two resistors, the balancing point is obtained at \(75\,\text{cm}\) from the left end of the bridge wire. Then the initial values of the resistors connected in the left and right gaps of the bridge respectively are

• A. \(18\,\Omega,\;54\,\Omega\)
• B. \(6\,\Omega,\;18\,\Omega\)
• C. \(12\,\Omega,\;36\,\Omega\)
• D. \(24\,\Omega,\;72\,\Omega\)

Hint:

For a balanced meter bridge, \[ \boxed{ \frac{R_1}{R_2} = \frac{l}{100-l}. } \] If resistance is added in series to one gap, simply replace that resistance by its new value and apply the balance condition again.

Answer 1

The Correct Option is B