\( 5 \times 10^{-6} \, \text{C} \)
\( 5 \times 10^{-5} \, \text{C} \)
Provided information:
The charge on a capacitor is calculated using: \[ Q = C \cdot V \]
\[ Q = 5 \times 10^{-6} \, \text{F} \times 10 \, \text{V} = 5 \times 10^{-5} \, \text{C} \]
The capacitor's charge is \( 5 \times 10^{-5} \, \text{C} \).
Option 2: \( 5 \times 10^{-5} \, \text{C} \)
A 10 $\mu\text{C}$ charge is placed in an electric field of $ 5 \times 10^3 \text{N/C} $. What is the force experienced by the charge?