Question:medium

A capacitor has a capacitance of $ 5 \, \mu\text{F} $ and a potential difference of $ 10 \, \text{V} $ is applied across it. What is the charge on the capacitor?

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Remember: The charge on a capacitor is the product of the capacitance and the potential difference across it.
Updated On: Nov 26, 2025
  • \( 5 \times 10^{-6} \, \text{C} \)

  • \( 5 \times 10^{-5} \, \text{C} \)

  • \( 5 \times 10^{-7} \, \text{C} \)
  • \( 5 \times 10^{-8} \, \text{C} \)
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The Correct Option is B

Solution and Explanation

Determine Capacitor Charge

Provided information:

  • Capacitance \( C = 5 \, \mu\text{F} = 5 \times 10^{-6} \, \text{F} \)
  • Voltage \( V = 10 \, \text{V} \)

Step 1: Identify the governing equation

The charge on a capacitor is calculated using: \[ Q = C \cdot V \]

Step 2: Input given parameters

\[ Q = 5 \times 10^{-6} \, \text{F} \times 10 \, \text{V} = 5 \times 10^{-5} \, \text{C} \]

Result:

The capacitor's charge is \( 5 \times 10^{-5} \, \text{C} \).

Correct Choice:

Option 2: \( 5 \times 10^{-5} \, \text{C} \)

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