Question:medium

When $\psi_A$ and $\psi_B$ are the wave functions of atomic orbitals, then $\sigma^*$ is represented by :

Updated On: Jan 13, 2026
  • $\psi_A - 2\psi_B$
  • $\psi_A - \psi_B$
  • $\psi_A + 2\psi_B$
  • $\psi_A + \psi_B$
Show Solution

The Correct Option is B

Solution and Explanation

Molecular orbitals arise from the linear combination of atomic orbitals. For diatomic molecules, this results in bonding and antibonding orbitals.

The wave functions of atomic orbitals from atoms A and B are denoted as \(\psi_A\) and \(\psi_B\), respectively.

Atomic orbitals combine constructively or destructively to form molecular orbitals:

  • Constructive combination yields a bonding molecular orbital, typically represented as \(\psi_A + \psi_B\).
  • Destructive combination yields an antibonding molecular orbital, denoted by \(\sigma^*\), and is typically represented as \(\psi_A - \psi_B\).

The antibonding molecular orbital, \(\sigma^*\), is formed through destructive interference of wave functions, creating a nodal plane between nuclei with low electron density.

Based on these principles, the accurate representation of \(\sigma^*\) is:

Correct Answer: \(\psi_A - \psi_B\)

Explanations for ruling out other options:

  • \(\psi_A - 2\psi_B\): This mathematical form is not a standard representation for molecular orbitals.
  • \(\psi_A + 2\psi_B\): This would intensify constructive interference and does not describe an antibonding orbital.
  • \(\psi_A + \psi_B\): This expression is characteristic of a bonding orbital, not an antibonding one.
Was this answer helpful?
0