Question:medium

When an external resistor of resistance \(18\,\Omega\) is connected to a cell, the current drawn from the cell is \(I\). If another \(18\,\Omega\) resistor is connected parallel to the first resistor, the current drawn from the cell increases by \(90\%\), then the internal resistance of the cell is

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For a cell, \[ I=\frac{E}{R+r}. \] Whenever the external resistance changes, write the current expression before and after the change, then use the given percentage increase/decrease to determine the internal resistance.
Updated On: Jul 29, 2026
  • \(2\,\Omega\)
  • \(0.5\,\Omega\)
  • \(1.5\,\Omega\)
  • \(1\,\Omega\)
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The Correct Option is D

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