Question

When \(160\,\mathrm{g}\) of methane was burnt in air at STP, \(5\%\) of it remained. At \(273\,\mathrm{K}\) and \(1\,\mathrm{bar}\) pressure, air contains \(20\%\) of \(\mathrm{O_2}\) by volume. What is the approximate volume (in L) of air consumed? \[ \text{(At STP molar volume }=22.71\,\mathrm{L}) \]

• A. \(2157.45\)
• B. \(215.74\)
• C. \(21574.5\)
• D. \(431.49\)

Hint:

For combustion of methane, \[ \boxed{ \mathrm{CH_4+2O_2\rightarrow CO_2+2H_2O} } \] If air contains \(20\%\) oxygen, \[ \boxed{ V_{\text{air}}=\frac{V_{O_2}}{0.20}. } \]

Answer 1

The Correct Option is A