Question

The expression of average speed (u avg) of molecules of a gas is given by

• A. \(\sqrt{\frac{8RT}{\pi m}}\)
• B. \(\sqrt{\frac{8RT}{\pi M}}\)
• C. \(\sqrt{\frac{3RT}{\pi m}}\)
• D. \(\sqrt{\frac{3RT}{m}}\)

Hint:

The average speed depends on the temperature and molar mass of the gas. The higher the temperature or lower the molar mass, the faster the molecules move.

Answer 1

The Correct Option is B

Based on the kinetic theory of gases, the mean molecular speed can be calculated using the following equation: \[ u_{\text{avg}} = \sqrt{\frac{8RT}{\pi M}}, \] in which \( R \) represents the universal gas constant, \( T \) denotes the temperature, and \( M \) signifies the gas's molar mass.