What is the value of the ratio\( \frac{\text{Area of the hexagon}}{\text{Area of the grey triangle}}\)?
A third approach uses the long diagonal AD to split the hexagon into two congruent trapezoids, without any trigonometry or coordinates.
The diagonal AD splits the regular hexagon into two congruent trapezoids, so each trapezoid, including ABCD, has exactly half the hexagon's area: \( \frac{3\sqrt{3}}{4}s^2 \).
Triangle ABD sits inside trapezoid ABCD, and equals that trapezoid's area minus the small corner triangle BCD. Triangle BCD has two sides of length \( s \) meeting at the hexagon's own interior angle of \( 120^{\circ} \) at vertex C, so its area is \( \frac{1}{2}(s)(s)\sin(120^{\circ}) = \frac{\sqrt{3}}{4}s^2 \).
So the area of ABD is \( \frac{3\sqrt{3}}{4}s^2 - \frac{\sqrt{3}}{4}s^2 = \frac{\sqrt{3}}{2}s^2 \).
Comparing this with the hexagon's area \( \frac{3\sqrt{3}}{2}s^2 \) gives a ratio of 3. So the correct answer is 3.
Statement: All flowers are beautiful. Some beautiful things are fragile.
Conclusion I: Some flowers are fragile.
Conclusion II: All beautiful things are flowers.