Question

What is the time period of a simple pendulum of length \( L \) and acceleration due to gravity \( g \)?

• A. \( 2\pi \sqrt{\frac{L}{g}} \)
• B. \( 2\pi \sqrt{\frac{g}{L}} \)
• C. \( \frac{2\pi}{\sqrt{L}} \)
• D. \( \frac{2\pi}{g} \)

Hint:

The time period of a simple pendulum depends on its length and the acceleration due to gravity but is independent of the mass of the pendulum.

Answer 1

The Correct Option is A

The formula for the period \( T \) of a simple pendulum is \( T = 2\pi \sqrt{\frac{L}{g}} \), where \( L \) represents the pendulum's length and \( g \) denotes the acceleration due to gravity. Consequently, option (1) is the correct choice.