Idea: Fully parenthesise by precedence, then move each operator after its operands.
Insert the implied brackets according to priority:
\[(A + (B * C)) - (D / E)\]
Convert innermost groups: $B * C \to BC*$ and $D / E \to DE/$. The tree now reads $((A) + (BC*)) - (DE/)$.
Postfix places the operator last. The plus node yields $A\,BC*\,+ = ABC*+$. The top minus node takes that whole left result and the right group $DE/$, appending the operator:
\[ABC*+ \;\; DE/ \;\; - \;=\; ABC*+DE/-\]
\[\boxed{A\,B\,C\,*\,+\,D\,E\,/\,-}\]