Question:medium

What is the oxidation state of Nickel in \(Ni(CO)_4\)?

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Carbon monoxide (\(CO\)) is a neutral ligand. When all ligands are neutral and the complex has no overall charge, the metal oxidation state is \(0\).
Updated On: Apr 29, 2026
  • \(+2\)
  • \(+1\)
  • \(0\)
  • \(-2\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Understanding the Question:
The goal is to determine the formal charge (oxidation state) assigned to the Nickel atom within the metal carbonyl complex.
Step 2: Key Formula or Approach:
The sum of the oxidation states of all atoms in a neutral molecule is zero.
Sum of charges = (Oxidation state of Metal) + (Total charge of Ligands).
Step 3: Detailed Explanation:
In the complex \(Ni(CO)_4\):
1. The complex is neutral (no charge on the coordination sphere).
2. The ligand is Carbon Monoxide (\(CO\)). \(CO\) is a neutral molecule, so its charge is \(0\).
Let \(x\) be the oxidation state of \(Ni\).
\[ x + 4 \times (\text{charge of } CO) = 0 \]
\[ x + 4(0) = 0 \]
\[ x = 0 \]
Step 4: Final Answer:
The oxidation state of Nickel is \(0\).
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