Question:medium

Oxidation number of H in NaH, CaH$_2$, and LiH, respectively is:

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In metal hydrides (e.g., NaH, CaH$_2$, LiH), hydrogen acts as a hydride ion (\( H^- \)) with an oxidation number of \(-1\). This is different from most other compounds, where hydrogen typically has an oxidation number of \(+1\).
Updated On: Nov 26, 2025
  • +1, +1, -1
  • -1, +1, +1
  • +1, +1, +1
  • -1, -1, -1
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The Correct Option is D

Solution and Explanation

1. Oxidation State Determination for NaH (Sodium Hydride)
Sodium (\(Na\)), an alkali metal, consistently exhibits an oxidation state of \(+1\).
For the neutral compound NaH, hydrogen's oxidation state must be \(-1\) to achieve charge neutrality. 2. Oxidation State Determination for CaH$_2$ (Calcium Hydride)
Calcium (\(Ca\)), an alkaline earth metal, has an oxidation state of \(+2\).
As CaH$_2$ is a neutral species, hydrogen's oxidation state must be \(-1\) to balance the charge.3. Oxidation State Determination for LiH (Lithium Hydride)
Lithium (\(Li\)), an alkali metal, possesses an oxidation state of \(+1\).
In the neutral compound LiH, hydrogen's oxidation state is determined to be \(-1\) for charge balance.Conclusion: The determined oxidation states for hydrogen in NaH, CaH$_2$, and LiH are \(-1\), \(-1\), and \(-1\), respectively. This corresponds to Option (d) \(-1, -1, -1\).
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