In which compound does Mn (Manganese) have its highest oxidation state?

Question

Consider the reactions: 1. \(NaCl+K_{2}Cr_{2}O_{7}+H_{2}SO_{4} \rightarrow A + ...\) 2. \(A + NaOH \rightarrow B + ...\) 3. \(B + H_{2}SO_{4}+H_{2}O_{2} \rightarrow C + ...\) In the product 'C', X is the number of \(O_{2}^{2-}\) units, Y is the total number of oxygen atoms, and Z is the oxidation state of Cr. The value of \(X+Y+Z\) is__.

Answer 1

We will determine the oxidation state of Mn in each compound:

(1) MnO\(_2\):

Let the oxidation state of Mn be \( x \): \[ x + 2(-2) = 0 \Rightarrow x = +4 \]

(2) MnO\(_4^-\):

\[ x + 4(-2) = -1 \Rightarrow x = +7 \]

(3) KMnO\(_4\):

Potassium is +1, and each oxygen is -2: \[ +1 + x + 4(-2) = 0 \Rightarrow x = +7 \]

(4) Mn\(_2\)O\(_3\):

\[ 2x + 3(-2) = 0 \Rightarrow 2x = +6 \Rightarrow x = +3 \]

The highest oxidation state is \( +7 \), found in both MnO\(_4^-\) and KMnO\(_4\). Therefore, KMnO\(_4\) is the correct compound from the given choices.

List I	List II
(A) Cr₂O₇²⁻	(I) +3
(B) MnO₄⁻	(II) +5
(C) VO₃⁻	(III) +7
(D) FeF₆³⁻	(IV) +6

In which compound does Mn (Manganese) have its highest oxidation state?

Show Hint

The Correct Option is C

Solution and Explanation

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