Question:medium

What is the energy stored in a capacitor of capacitance \( C = 10 \, \mu\text{F} \) when a potential difference of \( V = 20 \, \text{V} \) is applied across it?

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Remember: \( \text{Energy} = \frac{1}{2} C V^2 \) for capacitors. Ensure the units of capacitance and voltage are consistent.
Updated On: Nov 26, 2025
  • \( 0.01 \, \text{J} \)
  • \( 2 \, \text{J} \)
  • \( 4 \, \text{J} \)
  • \( 0.1 \, \text{J} \)
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The Correct Option is A

Solution and Explanation

Step 1: Apply the capacitor energy storage formula \[\text{Energy} = \frac{1}{2} C V^2\]Provided values: - Capacitance \( C = 10 \, \mu\text{F} = 10 \times 10^{-6} \, \text{F} \) - Voltage \( V = 20 \, \text{V} \)Calculation: \[\text{Energy} = \frac{1}{2} \times (10 \times 10^{-6}) \times (20)^2 = 0.01 \, \text{J}\]Answer: The energy stored in the capacitor is \( 0.01 \, \text{J} \), corresponding to option (1).
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