Step 1: Apply the capacitor energy storage formula \[\text{Energy} = \frac{1}{2} C V^2\]Provided values: - Capacitance \( C = 10 \, \mu\text{F} = 10 \times 10^{-6} \, \text{F} \) - Voltage \( V = 20 \, \text{V} \)Calculation: \[\text{Energy} = \frac{1}{2} \times (10 \times 10^{-6}) \times (20)^2 = 0.01 \, \text{J}\]Answer: The energy stored in the capacitor is \( 0.01 \, \text{J} \), corresponding to option (1).