Question:easy

What is the dimensional formula of electric potential?

Show Hint

Remember the important dimensional formulas: \[ \begin{aligned} \text{Work} &=[ML^{2}T^{-2}],\\ \text{Charge} &=[AT],\\ \text{Potential} &=\frac{\text{Work}}{\text{Charge}} =[ML^{2}T^{-3}A^{-1}],\\ \text{Resistance} &=\frac{\text{Potential}}{\text{Current}} =[ML^{2}T^{-3}A^{-2}]. \end{aligned} \] Always derive the dimensions from the defining formula instead of memorizing them separately.
  • \( [L^{2}T^{-3}A^{-1}] \)
  • \( [L^{2}T^{-2}A^{-1}] \)
  • \( [ML^{2}T^{-3}A^{-2}] \)
  • \( [L^{2}T^{-2}A^{-2}] \)
Show Solution

The Correct Option is C

Solution and Explanation

Electric potential is defined as $V = W/q$, where $W$ is work done and $q$ is charge. With $[W] = ML^2T^{-2}$ and $[q] = AT$, substituting gives $[V] = ML^2T^{-2}/(AT) = ML^2T^{-3}A^{-1}$.
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