The work performed by a force is calculated using the formula:
\[
W = F \times d \times \cos \theta
\]
In this scenario:
- \( F = 10 \, \text{N} \) represents the applied force.
- \( d = 3 \, \text{m} \) denotes the displacement of the object.
- \( \theta = 0^\circ \) indicates that the force acts in the direction of movement, as \( \cos 0^\circ = 1 \).
Consequently, the work done is:
\[
W = 10 \times 3 \times \cos 0^\circ = 10 \times 3 \times 1 = 30 \, \text{J}
\]
Therefore, the work done amounts to \( W = 30 \, \text{J} \).