Question:medium

Wavenumber for a radiation having $5800 \, \mathring{A}$ wavelength is $x \times 10 \, \text{cm}^{-1}$. The value of $x$ is _________

Updated On: Jan 13, 2026
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Correct Answer: 1724

Solution and Explanation

The formula for wavenumber is provided:

$$ \bar{v} = \frac{1}{\lambda} \Rightarrow \frac{1}{5800 \times 10^{-8}} \, \text{cm}^{-1} $$

The equation is simplified as follows:

$$ \Rightarrow \frac{10^8}{5800} \Rightarrow \frac{10^6}{58} $$
$$ \Rightarrow \frac{100000}{58} \times 10 $$
$$ \Rightarrow 1724.13 \times 10 $$
$$ \Rightarrow 1724 $$

Therefore, the wavenumber is 1724 cm-1.

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