Question

Two slits in Young’s double slit experiment are 1.5 mm apart and the screen is placed at a distance of 1 m from the slits. If the wavelength of light used is \(600 \times 10^{-9}\, \text{m}\), then the fringe separation is:

• A. \(4 \times 10^{-5}\, \text{m}\)
• B. \(9 \times 10^{-8}\, \text{m}\)
• C. \(4 \times 10^{-7}\, \text{m}\)
• D. \(4 \times 10^{-4}\, \text{m}\)

Answer 1

The Correct Option is D

The fringe separation (β) in Young's double-slit experiment is calculated using the formula:

$\beta = \frac{\lambda D}{d}$

Here,

λ denotes the wavelength of the light.

D represents the distance from the slits to the screen.

d signifies the separation between the slits.

Provided values:

λ = 600 × 10^-9 m; D = 1 m; d = 1.5 mm, which is equivalent to 1.5 × 10^-3 m.

The fringe separation is calculated as follows:

$\beta = \frac{(600 \times 10^{-9} \text{ m})(1 \text{ m})}{1.5 \times 10^{-3} \text{ m}} = 4 \times 10^{-4} \text{ m}$