Question:medium

Two rain drops of same radius '\(r\)' falling with same terminal velocity '\(V\)' merge and form bigger drop of radius '\(R\)'. The terminal velocity of big drop is

Show Hint

Terminal velocity varies as the square of the radius, and volume is conserved on merging.
Updated On: Oct 1, 2026
  • \(\frac{VR^2}{r^2}\)
  • \(\frac{2VR}{r}\)
  • \(\frac{VR}{r}\)
  • \(Vr^2/R^2\)
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Compare big and small drop
$\frac{V_{big}}{V_{small}}=\left(\frac{R}{r}\right)^2$ because the other quantities are the same. Hence $V_{big}=V\frac{R^2}{r^2}$. Option (A).
Numerically $\frac{R}{r}=2^{1/3}$, so the speed increases by about $1.59$ times.

Final Answer:
Option (A). \[ \boxed{\text{(A)}} \]
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