Question:medium

Two pipes A, B can fill a tank in 24 min and 32 min respectively. If both pipes are opened simultaneously, after how much time should B be closed so that the tank is full in 18 min?

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In variable-time pipe problems, keep one pipe running the full duration and treat the other for \(t\) minutes. Add their work (rate \(\times\) time) to equal 1 full tank.

Updated On: Jul 16, 2026
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The Correct Option is A

Solution and Explanation

Step 1: A's rate is \(\dfrac{1}{24}\) tank/min and B's rate is \(\dfrac{1}{32}\) tank/min. Let B run for \(t\) minutes while A runs for the full 18 minutes.

Step 2: The total work equation is \(18\times\dfrac{1}{24}+t\times\dfrac{1}{32}=1\), i.e. \(\dfrac{3}{4}+\dfrac{t}{32}=1\).

Step 3: Solving, \(\dfrac{t}{32}=\dfrac{1}{4}\), so \(t=8\). \[ \boxed{8\ \text{minutes}} \]
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