Two monomers in maltose are :

Question

Given below are two statements:
Statement I: Sucrose is dextrorotatory. However, sucrose upon hydrolysis gives a solution having mixture of products. This solution shows laevorotation.
Statement II: Hydrolysis of sucrose gives glucose and fructose. Since the laevorotation of glucose is more than the dextrorotation of fructose, the resulting solution becomes laevorotatory.
In the light of the above statements, choose the correct answer from the options given below.

Answer 1

Maltose is a disaccharide composed of two monomeric units of glucose. To correctly answer this question, we need to identify the specific isomer forms of these glucose units that constitute maltose. Maltose is formed through a glycosidic bond between two glucose molecules, specifically:

\alpha-D-glucose
\alpha-D-glucose

This disaccharide is synthesized when a molecule of water is removed from two glucose units in a condensation reaction, resulting in an \alpha-(1→4) glycosidic linkage. Both glucose units in maltose are in the \alpha-form.

Let's briefly review why the other options are incorrect:

Option with \alpha-D-glucose and \alpha-D-galactose is incorrect because this combination forms lactose, another disaccharide.
Option with \alpha-D-glucose and \beta-D-glucose is incorrect because both units in maltose are in the \alpha-form, not mixed with \beta-form.
Option with \alpha-D-glucose and \alpha-D-Fructose forms sucrose, another common disaccharide.

Therefore, the correct answer is indeed: \alpha-D-glucose and \alpha-D-glucose.

Answer 2

Maltose is a disaccharide composed of two monomeric units of glucose. To correctly answer this question, we need to identify the specific isomer forms of these glucose units that constitute maltose. Maltose is formed through a glycosidic bond between two glucose molecules, specifically:

\alpha-D-glucose
\alpha-D-glucose

This disaccharide is synthesized when a molecule of water is removed from two glucose units in a condensation reaction, resulting in an \alpha-(1→4) glycosidic linkage. Both glucose units in maltose are in the \alpha-form.

Let's briefly review why the other options are incorrect:

Option with \alpha-D-glucose and \alpha-D-galactose is incorrect because this combination forms lactose, another disaccharide.
Option with \alpha-D-glucose and \beta-D-glucose is incorrect because both units in maltose are in the \alpha-form, not mixed with \beta-form.
Option with \alpha-D-glucose and \alpha-D-Fructose forms sucrose, another common disaccharide.

Therefore, the correct answer is indeed: \alpha-D-glucose and \alpha-D-glucose.

Two monomers in maltose are :

The Correct Option is A

Solution and Explanation

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