Two metal rods \(A\) and \(B\) have lengths in the ratio \(1:2\), thermal conductivities in the ratio \(1:2\) and cross-sectional areas in the ratio \(1:4\). The ends of the two rods are maintained between the same temperature difference. Then the ratio of heat currents
\[
\left(\frac{H_A}{H_B}\right)
\]
is
Show Hint
For steady-state conduction,
\[
H=\frac{kA\Delta T}{L}.
\]
Heat current is directly proportional to thermal conductivity and area, but inversely proportional to length.