When two identical sphere come in contact with each other, the total charge on them is equally distribute.

\(\frac{kQ^2}{d^2}\)=F

F=\(\frac{k9Q^2}{16×\frac{d^2}{4}}−\frac{k3Q^2}{8×\frac{d^2}{4}}\)
=\(\frac{9kQ^2}{4d^2}−\frac{3kQ^2}{2d^2}\)
=\(\frac{kQ^2}{d^2}[\frac{9}{4}−\frac{3}{2}]\)
=\(\frac{6}{8}F\)
=\(\frac{3}{4}F\)
So, the correct option is (B): \(\frac{3}{4}F\)