Question:medium

Two different adiabatic paths for the same gas intersect two isothermal curves as shown in the \(P-V\) diagram. The relation between the ratio \(\frac{V_a}{V_d}\) and the ratio \(\frac{V_b}{V_c}\) is:
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Updated On: Mar 25, 2026
  • \(\frac{V_a}{V_d} = \left(\frac{V_b}{V_c}\right)^{-1}\)
  • \(\frac{V_a}{V_d} \neq \frac{V_b}{V_c}\)
  • \(\frac{V_a}{V_d} = \frac{V_b}{V_c}\)
  • \(\frac{V_a}{V_d} = \left(\frac{V_b}{V_c}\right)^2\)
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The Correct Option is C

Solution and Explanation

To address the problem, it is necessary to delineate the attributes of adiabatic and isothermal processes as illustrated on the \( P-V \) diagram.

The diagram displays two adiabatic paths intersecting with two isothermal curves. Points \(a, b, c,\) and \(d\) represent specific states defined by volume and pressure. Four volume values are provided: \(V_a, V_d, V_b,\) and \(V_c\).

Concept Definitions:

  • Isothermal Process: A thermodynamic process characterized by a constant temperature. For an ideal gas, this is described by \(PV = \text{constant}\).
  • Adiabatic Process: A thermodynamic process involving no heat transfer between the system and its surroundings. Its governing equation is \(PV^\gamma = \text{constant}\), where \( \gamma \) denotes the heat capacity ratio.

Derivation:

  • The process \(a \to d\) is identified as isothermal because points \(a\) and \(d\) share the same isothermal curve, indicated by their volume and pressure.
  • Similarly, the process \(b \to c\) is isothermal as points \(b\) and \(c\) are on the same isothermal curve.
  • Both processes \(a \to b\) and \(d \to c\) are adiabatic, connecting states at distinct intermediate temperatures.

For adiabatic processes occurring between the same pair of isotherms:

  • The relationship derived is \( \frac{V_a}{V_d} = \frac{V_b}{V_c} \).
  • This equality arises from the dependence of these ratios on the initial and final conditions between intersecting isothermal curves.

Consequently, the validated relation is: \(\frac{V_a}{V_d} = \frac{V_b}{V_c}\).

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