The probability of rolling a sum of at least 10 with two dice is calculated as follows. The total number of possible outcomes when rolling two dice is \(6 \times 6 = 36\), as each die has 6 faces.
The outcomes resulting in a sum of at least 10 are:
There are 6 such favorable outcomes. The probability is the ratio of favorable outcomes to the total possible outcomes:
\(\frac{6}{36} = \frac{1}{6}\)
Consequently, the probability that the sum of the numbers on two dice is at least 10 is \(\frac{1}{6}\).
If a random variable X has the following probability distribution values:
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
|---|---|---|---|---|---|---|---|---|
| P(X) | 1/12 | 1/12 | 1/12 | 1/12 | 1/12 | 1/12 | 1/12 | 1/12 |
Then P(X ≥ 6) has the value: