Question:medium

A die was thrown \( n \) times until the lowest number on the die appeared. If the mean is \( \frac{n}{g} \), then what is the value of \( n \)?

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When dealing with dice problems, consider the probabilities of rolling the lowest numbers and use those to form equations.
Updated On: Nov 26, 2025
  • \( 2 \)
  • \( 3 \)
  • \( 4 \)
  • \( 5 \)
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The Correct Option is B

Solution and Explanation

A die is rolled \( n \) times until the smallest observed value appears. The mean of these rolls is given by \( \frac{n}{g} \), where \( g \) denotes the smallest number observed. The solution proceeds as follows:

Step 1: Contextual understanding. A standard die has faces numbered 1 through 6. The experiment involves \( n \) rolls, and the focus is on the minimum value observed across these rolls. The formula for the mean is provided as \( \frac{n}{g} \), with \( n \) being the count of rolls and \( g \) being the minimum value shown on the die.

Step 2: Outcome analysis. The minimum possible value on a die roll ranges from 1 to 6. The mean calculation is dependent on both the total number of rolls and the smallest value encountered during those rolls.

Step 3: Derivation of \( n \). To determine \( n \), the formula \( \frac{n}{g} \) is utilized. Assuming a standard die and a uniform distribution of outcomes, the most probable minimum value \( g \) is 1. Substituting \( g = 1 \) into the formula yields: \[ \text{Mean} = \frac{n}{1} = n \] Consequently, \( n \) is equal to the mean.

Step 4: Conclusion. Based on the provided information, \( n \) represents the number of throws. The correct value is \( \boxed{3} \).

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