Question

Two coils P and Q have mutual inductance 'M' H. If the current in the coil P is \(I = I_0sinωt\), then the maximum value of e.m.f. induced in coil Q is

• A. \(\frac{ω}{MI_0}\)
• B. \(\frac{Mω}{I_0}\)
• C. \(MωI_0\)
• D. \(\frac{MI_0}{ω}\)

Hint:

The induced emf is M times the rate of change of current in the primary.

Answer 1

The Correct Option is C

Step 1: Use flux linkage.
Flux through Q is $\phi = MI = MI_0\sin\omega t$.

Step 2: Faraday law.
$e = -d\phi/dt = -MI_0\omega\cos\omega t$.

Step 3: Maximum.
$|e|_{max} = M\omega I_0$.

Final Answer:
Option (C). \[ \boxed{M\omega I_0} \]