Question:medium

If \( L \) is the inductance and \( R \) is the resistance, then the unit of \( \frac{L}{R} \) is:

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The ratio \( \frac{L}{R} \) represents the time constant (\( \tau \)) in an \( RL \) circuit, which determines the rate of exponential decay of current or voltage.
Updated On: Jan 13, 2026
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Solution and Explanation

Step 1: Units of Inductance and Resistance.
Inductance \( L \) is in henries (\( H \)), and resistance \( R \) is in ohms (\( \Omega \)).The henry (\( H \)) is defined as:\[1 \, H = 1 \, \text{ohm-second} \, (\Omega \cdot s).\]Step 2: Derive the Unit of \( \frac{L}{R} \).
The unit of \( \frac{L}{R} \) is:\[\text{Unit of } \frac{L}{R} = \frac{\text{Unit of } L}{\text{Unit of } R} = \frac{\text{henry}}{\text{ohm}}.\]Using \( 1 \, H = \Omega \cdot s \):\[\frac{\text{henry}}{\text{ohm}} = \frac{\Omega \cdot s}{\Omega}.\]Simplification yields:\[\frac{\text{henry}}{\text{ohm}} = \text{seconds (s)}.\]Step 3: Final Answer.
The unit of \( \frac{L}{R} \) is:\[\boxed{\text{seconds (s)}}.\]
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