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Two vehicles, one with a higher velocity than the other, are in motion. They are either moving towards each other or in the same direction. The velocity of the slower vehicle is 60 km/h. The time until they meet is:
Determine the distance covered by the slower vehicle in the scenario where they travel towards each other.
Combined velocity = \( v + 60 \) km/h.
Time elapsed = 1.5 hours.
\[ \text{Distance} = (v + 60) \times 1.5 \]
Relative velocity = \( v - 60 \) km/h.
Time elapsed = 10.5 hours.
\[ \text{Distance} = (v - 60) \times 10.5 \]
The total distance covered in both scenarios is the same:
\[ (v + 60) \times 1.5 = (v - 60) \times 10.5 \]
\[ 1.5v + 90 = 10.5v - 630 \]
\[ 90 + 630 = 10.5v - 1.5v \]
\[ 720 = 9v \]
\[ v = \frac{720}{9} = 80 \]
Therefore, the velocity of the faster vehicle is \( \boxed{80 \text{ km/h}} \).
Using the time from the first scenario (1.5 hours) and the velocity of the slower vehicle (60 km/h):
\[ \text{Distance} = 60 \times 1.5 = \boxed{90 \text{ km}} \]
The distance covered by the slower vehicle in the first case is \( \boxed{90 \text{ km}} \). (Correct Option: C)