Question:medium

Two bodies are projected from the same point with the same initial velocity 'u' making angles '$\theta$' and ($90^\circ-\theta$) with the horizontal in opposite directions. The horizontal distance between their positions when the bodies are at their maximum heights is

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For complementary angles of projection ($\theta$ and $90-\theta$), the horizontal ranges are equal. The maximum heights occur at $R/2$.
Updated On: Mar 26, 2026
  • $\frac{u^2}{2g}(\sin^2 \theta - \cos^2 \theta)$
  • $\frac{u^2 \sin 2\theta}{2g}$
  • $\frac{u^2}{g}$
  • $\frac{u^2 \sin 2(90^\circ-\theta)}{g}$
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The Correct Option is D

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