Question:medium

A block of mass 5 kg is placed on a frictionless surface and a force of 20 N is applied horizontally. What is the acceleration of the block?

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For frictionless surfaces, use Newton's second law directly to find acceleration.
Updated On: Nov 26, 2025
  • 4 m/s\(^2\)
  • 2 m/s\(^2\)
  • 5 m/s\(^2\)
  • 10 m/s\(^2\)
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The Correct Option is A

Solution and Explanation


Step 1: Apply Newton's second law, \( F = ma \).
Given: Force \( F = 20 \, \text{N} \), mass \( m = 5 \, \text{kg} \).
\[ a = \frac{F}{m} = \frac{20}{5} = 4 \, \text{m/s}^2 \] Step 2: Verification: The surface is frictionless, so no opposing forces act on the object. The calculated acceleration is: \[ a = 4 \, \text{m/s}^2 \] This result corresponds to option (1).
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