Chromium (Cr) has atomic number \( Z = 24 \), indicating 24 electrons. Its electron configuration is:
\[
\text{Cr: } [Ar] 3d^5 4s^1
\]
Now, consider the azimuthal quantum number \( l \) and its associated orbitals:
- When \( l = 1 \), the orbitals are \( p \)-orbitals, which can hold a total of 6 electrons. In chromium, the \( 3p \) and \( 4p \) orbitals contribute to this, each capable of holding 6 electrons. Therefore, for \( l = 1 \), there are 6 electrons.
- When \( l = 2 \), the orbitals are \( d \)-orbitals, with a maximum capacity of 10 electrons. In chromium's configuration \( 3d^5 \), the \( 3d \) orbitals contain 5 electrons.
Combining these, for \( l = 1 \), there are 6 electrons (from \( p \)-orbitals), and for \( l = 2 \), there are 10 electrons (from \( d \)-orbitals). The total number of electrons for these \( l \) values is:
\[
6 \text{ (from \( p \)-orbitals)} + 10 \text{ (from \( d \)-orbitals)} = 12 \text{ electrons}.
\]
Thus, chromium has a total of 12 electrons with \( l = 1 \) and \( l = 2 \).
Consequently, the correct answer is (2) 12.