The sphere's volume is: \(\ V = \frac{4}{3} \pi r^3 \).
The combined volume of three spheres: \(\ V_{\text{total}} = \frac{4}{3} \pi (3^3 + 4^3 + 5^3) = \frac{4}{3} \pi (27 + 64 + 125) = \frac{4}{3} \pi (216) \).
The new sphere's volume is: \(\ V_{\text{new}} = \frac{4}{3} \pi r^3 \).
Solve for \(r\) by equating volumes: \(\ r^3 = \frac{216}{\frac{4}{3} \pi} \quad \Rightarrow \quad r = 6 \, \text{cm} \).
Therefore, the answer is 6 cm.