To solve the problem of finding the angle \(\theta\) subtended by arc \(PQ\) at the center of the circle, we need to use the formula for arc length:
\(L = r \theta\)
Here, \(L\) is the arc length, \(r\) is the radius of the circle, and \(\theta\) is the angle in radians.
Given:
Using the formula, we can find \(\theta\) as follows:
\(\theta = \frac{L}{r} = \frac{11 \text{ cm}}{6.3 \text{ cm}}\)
Calculating this gives:
\(\theta \approx 1.746 \text{ radians}\)
To convert radians to degrees, we use the conversion factor:
\(1 \text{ radian} = \frac{180}{\pi} \text{ degrees}\)
Therefore,
\(\theta \approx 1.746 \times \frac{180}{\pi} \approx 100^{\circ}\)
This matches with the given correct answer option.
In the figure O is the centre of the circle and A, B, C are points on the circle. AOB = 50^, BOC = 80^. 