Question:medium

Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

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When dealing with decimals like 6.3 in arc length or area of sector problems, they are usually multiples of 7. Using \(\pi = 22/7\) often leads to easy cancellations.
Updated On: Feb 23, 2026
  • \(10^{\circ}\)
  • \(60^{\circ}\)
  • \(45^{\circ}\)
  • \(100^{\circ}\)
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The Correct Option is D

Solution and Explanation

To solve the problem of finding the angle \(\theta\) subtended by arc \(PQ\) at the center of the circle, we need to use the formula for arc length:

\(L = r \theta\)

Here, \(L\) is the arc length, \(r\) is the radius of the circle, and \(\theta\) is the angle in radians.

Given:

  • Arc \(PQ = 11 \text{ cm}\)
  • Radius \(r = 6.3 \text{ cm}\)

Using the formula, we can find \(\theta\) as follows:

\(\theta = \frac{L}{r} = \frac{11 \text{ cm}}{6.3 \text{ cm}}\)

Calculating this gives:

\(\theta \approx 1.746 \text{ radians}\)

To convert radians to degrees, we use the conversion factor:

\(1 \text{ radian} = \frac{180}{\pi} \text{ degrees}\)

Therefore,

\(\theta \approx 1.746 \times \frac{180}{\pi} \approx 100^{\circ}\)

This matches with the given correct answer option.

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