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The roots of the quadratic equation x² - 5x + k = 0 are real and distinct. What is the range of values for k?
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For quadratic equations, use the discriminant: \( \Delta>0 \) for real and distinct roots, \( \Delta = 0 \) for equal roots.
JEECUP - 2025
JEECUP
Updated On:
Mar 31, 2026
\( k<\frac{25}{4} \)
\( k>\frac{25}{4} \)
\( k \leq \frac{25}{4} \)
\( k \geq \frac{25}{4} \)
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The Correct Option is
A
Solution and Explanation
To determine the range of \( k \) for real and distinct roots, we use these steps:
For \( ax^2 + bx + c = 0 \), real and distinct roots require the discriminant \( \Delta>0 \).
Given \( x^2 - 5x + k = 0 \), then \( a = 1 \), \( b = -5 \), \( c = k \).
Calculate the discriminant: \[ \Delta = b^2 - 4ac = (-5)^2 - 4 \times 1 \times k = 25 - 4k. \]
Apply the condition for real and distinct roots: \[ 25 - 4k>0. \]
Solve the inequality: \[ 25>4k \implies 4k<25 \implies k<\frac{25}{4}. \]
Compare with choices: \( k<\frac{25}{4} \) matches option (A).
Therefore, the solution is: \[ \boxed{k<\frac{25}{4}} \]
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