To solve this problem, we need to check under which conditions the three Carnot engines operating in series are equally efficient. The efficiency of a Carnot engine is given by:
\(\eta = 1 - \frac{T_{\text{C}}}{T_{\text{H}}}\)
where \( T_{\text{H}} \) is the temperature of the heat source and \( T_{\text{C}} \) is the temperature of the heat sink.
For the three engines to be equally efficient:
For the engines to have equal efficiency:
\(\frac{T_2}{T_1} = \frac{T_3}{T_2} = \frac{T_4}{T_3}\)
This leads to the ratios:
Solving these, we find:
\(k^3 T_1 = T_4 \implies k = \left(\frac{T_4}{T_1}\right)^{1/3}\)
Thus, the equations for \( T_2 \) and \( T_3 \) become:
So, under these conditions, the engines are equally efficient. Therefore, the correct answer is:
\(T_2 = \left(T_1^2 T_4\right)^{1/3} ; T_3 = \left(T_1 T_4^2\right)^{1/3}\)