Question:medium

The work functions of cesium (Cs) and lithium (Li) metals are 1.9 eV and 2.5 eV, respectively. If we incident a light of wavelength 550 nm on these two metal surfaces, then photo-electric effect is possible for the case of:

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For the photoelectric effect to occur, the energy of the incoming light must be greater than the work function of the material.
Updated On: Mar 25, 2026
  • Li only
  • Cs only
  • Neither Cs nor Li
  • Both Cs and Li
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The Correct Option is B

Solution and Explanation

The incident photon's energy is calculated as: \[ E = \frac{1240}{\lambda} = \frac{1240}{550} \approx 2.25 \, \text{eV} \]. Photoelectric effect necessitates the photon energy exceeding the metal's work function.

For Cesium (work function = 1.9 eV): 

As \( 2.25 \, \text{eV} > 1.9 \, \text{eV} \), photoelectric effect is feasible with Cs. 

For Lithium (work function = 2.5 eV): 

Since \( 2.25 \, \text{eV} < 2.5 \, \text{eV} \), photoelectric effect is not possible with Li. 

Therefore, the solution is \( \boxed{\text{Cs only}} \).

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