Step 1: Understanding the Concept:
A Wheatstone bridge is balanced when the ratio of resistances in adjacent arms is equal: $\frac{P}{Q} = \frac{R}{S}$.
Step 2: Formula Application:
Assuming the order given is $P=2, Q=6, R=X, S=12$:
$$\frac{2}{6} = \frac{X}{12}$$
Step 3: Explanation:
$\frac{1}{3} = \frac{X}{12}$
$3X = 12 \implies X = 4$ $\Omega$.
Step 4: Final Answer:
The value of X is 4 $\Omega$.