The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between \( t = 0 \) to \( t = 4s \)?
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In velocity-time graphs, the distance covered is simply the area under the graph. Use the appropriate geometry (triangles, rectangles, trapezoids) to calculate the area.
The distance an object travels is equivalent to the area beneath its velocity-time graph. This particular graph comprises both trapezoidal and rectangular sections.
The total distance traveled is represented by the area under the graph between \( t = 0 \) and \( t = 4 \). Computation of this area from the graph yields:
\[
\text{Distance} = \text{Area under the graph} = 13 \, \text{m}
\]
