Question

The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between \( t = 0 \) to \( t = 4s \)? 


 

• A. 13 m
• B. 30 m
• C. 11 m
• D. 10 m

Hint:

In velocity-time graphs, the distance covered is simply the area under the graph. Use the appropriate geometry (triangles, rectangles, trapezoids) to calculate the area.

Answer 1

The Correct Option is A

The distance traversed by an object is equivalent to the area bounded by its velocity-time graph. The provided graph comprises both trapezoidal and rectangular sections. The total area delineated by the graph from \( t = 0 \) to \( t = 4 \) quantifies the distance traveled. The calculation of this area yields: \[ {Distance} = {Area under the graph} = 13 \, {m} \]