
The provided diagram illustrates a Wheatstone Bridge.
The condition for balancing the bridge is:

\[ \frac{V_{AB}}{V_{AD}} = \frac{V_{BC}}{V_{CD}}. \]
Inserting circuit values:
\[ \frac{12}{6 + x} = \frac{0.5}{0.5}. \]
Simplification yields:
\[ 12(0.5) = (6 + x)(0.5). \]
\[ 6 = 3 + 0.5x \implies x = 6 \, \Omega. \]
The resultant value is: \( x = 6 \, \Omega \).