Question:medium
The value of \( \sum_{n=1}^{10} \frac{528}{n(n+1)(n+2)} \) is equal to:
The value of \( \sum_{n=1}^{10} \frac{528}{n(n+1)(n+2)} \) is equal to:
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For a denominator with \( k \) factors, the difference is created by removing the first factor and the last factor: \( \frac{1}{n(n+1)...(n+k)} = \frac{1}{k} [ \frac{1}{\text{first } k} - \frac{1}{\text{last } k} ] \).
Updated On: Apr 6, 2026
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The Correct Option is A
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