{"@context":"https://schema.org/","@type":"Quiz","dateCreated":"2024-02-06T09:43:32.160Z","dateModified":"2026-01-13T12:42:38.835Z","typicalAgeRange":"11-18","educationalLevel":"JEE Main","assesses":"Mathematics - integral","educationalAlignment":[{"@type":"AlignmentObject","alignmentType":"educationalTopic","targetName":"integral"},{"@type":"AlignmentObject","alignmentType":"educationalSubject","targetName":"Mathematics"},{"@type":"AlignmentObject","alignmentType":"educationalExam","targetName":"JEE Main"}],"name":"Quiz about integral","about":{"@type":"Thing","name":"Mathematics - integral"},"hasPart":[{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"intermediate","name":"Question About integral","text":"The value of $$∫_{\\frac \\pi6}^{\\frac \\pi3}\\sqrt {1-sin2x\\ dx}$$ is}","encodingFormat":"text/markdown","comment":{"@type":"Comment","text":"\"\""},"suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/markdown","text":"

\$\\sqrt 2-\\sqrt 3+1\$

","comment":{"@type":"Comment","text":"\"\""}},{"@type":"Answer","position":1,"encodingFormat":"text/markdown","text":"

\$2\\sqrt 2-\\sqrt 3-1\$

","comment":{"@type":"Comment","text":"\"\""}},{"@type":"Answer","position":2,"encodingFormat":"text/markdown","text":"

\$2\\sqrt 2+\\sqrt 3-1\$

","comment":{"@type":"Comment","text":"\"\""}},{"@type":"Answer","position":3,"encodingFormat":"text/markdown","text":"

\$\\sqrt 2+\\sqrt 3-1\$

","comment":{"@type":"Comment","text":"\"\""}}],"acceptedAnswer":{"@type":"Answer","position":1,"encodingFormat":"text/markdown","text":"

\$2\\sqrt 2-\\sqrt 3-1\$

","comment":{"@type":"Comment","text":"\"\""},"answerExplanation":{"@type":"comment","text":"The correct option is (B): \$2\\sqrt 2-\\sqrt 3-1\$."}}}]}

The value of \(∫_{\frac \pi6}^{\frac \pi3}\sqrt {1-sin2x\ dx}\) is

The Correct Option is B

Solution and Explanation

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