Question:medium

The two ends of a rod of length ' \( x \) ' and uniform cross-sectional area ' \( A \) ' are kept at temperatures ' \( T_1 \) ' and ' \( T_2 \) ' respectively (\( T_1>T_2 \)). If the rate of heat transfer is ' \( Q/t \) ', through the rod in steady state, then the coefficient of thermal conductivity ' \( K \) ' is

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Fourier's Law of Heat Conduction: $Q = \frac{KA\Delta T t}{L}$.
Updated On: May 7, 2026
  • \( \frac{A Q}{tx(T_1-T_2)} \)
  • \( \frac{x Q}{t A(T_1-T_2)} \)
  • \( \frac{x A Q}{t(T_1-T_2)} \)
  • \( \frac{Q}{tx A(T_1-T_2)} \)
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
Heat transfer through a solid material by conduction is governed by Fourier's law of heat conduction.
In a steady state, the rate of heat flow is constant and uniform throughout the cross-section of the rod.
Step 2: Key Formula or Approach:
Fourier's law for one-dimensional heat conduction states that the rate of heat transfer \( H \) (which is \( Q/t \)) is proportional to the cross-sectional area \( A \) and the temperature gradient.
The formula is: \[ H = \frac{Q}{t} = \frac{K \cdot A \cdot \Delta T}{L} \] where \( K \) is the coefficient of thermal conductivity, \( A \) is the area, \( \Delta T \) is the temperature difference, and \( L \) is the length of the conductor.
Step 3: Detailed Explanation:
From the problem description, we have the following parameters: - Rate of heat transfer \( = \frac{Q}{t} \) - Length of the rod \( = x \) - Cross-sectional area \( = A \) - Temperature difference \( \Delta T = T_1 - T_2 \) (since \( T_1>T_2 \)) Substitute these specific variables into the standard heat conduction formula: \[ \frac{Q}{t} = \frac{K \cdot A \cdot (T_1 - T_2)}{x} \] We need to find the expression for the coefficient of thermal conductivity '\( K \)'. Rearrange the equation to solve for \( K \).
Multiply both sides by \( x \): \[ \left(\frac{Q}{t}\right) \cdot x = K \cdot A \cdot (T_1 - T_2) \] Now, divide both sides by \( A(T_1 - T_2) \): \[ K = \frac{\left(\frac{Q}{t}\right) \cdot x}{A \cdot (T_1 - T_2)} \] This can be rewritten more neatly as: \[ K = \frac{x Q}{t A (T_1 - T_2)} \] This expression matches option (B).
Step 4: Final Answer:
The coefficient of thermal conductivity is \( \frac{x Q}{t A(T_1-T_2)} \).
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