




To derive the truth table for the provided circuit, a step-by-step analysis of its logic gates is required. The circuit comprises two XOR gates feeding into an OR gate.
Circuit breakdown:
As both XOR gates share identical functionality and inputs, the OR gate’s output is dictated by the XOR condition itself. The truth table is constructed as follows:
| A | B | First XOR: A ⊕ B | Second XOR: A ⊕ B | Y = (A ⊕ B) OR (A ⊕ B) |
|---|---|---|---|---|
| 0 | 0 | 0 | 0 | 0 |
| 0 | 1 | 1 | 1 | 1 |
| 1 | 0 | 1 | 1 | 1 |
| 1 | 1 | 0 | 0 | 0 |
The resulting truth table for the circuit is presented above. Option 2 accurately reflects this derived truth table.
In the circuit shown, assuming the threshold voltage of the diode is negligibly small, then the voltage \( V_{AB} \) is correctly represented by:
The value of current \( I \) in the electrical circuit as given below, when the potential at \( A \) is equal to the potential at \( B \), will be _____ A. 
The Boolean expression $\mathrm{Y}=\mathrm{A} \overline{\mathrm{B}} \mathrm{C}+\overline{\mathrm{AC}}$ can be realised with which of the following gate configurations.
A. One 3-input AND gate, 3 NOT gates and one 2-input OR gate, One 2-input AND gate
B. One 3-input AND gate, 1 NOT gate, One 2-input NOR gate and one 2-input OR gate
C. 3-input OR gate, 3 NOT gates and one 2-input AND gate
Choose the correct answer from the options given below:
The truth table corresponding to the circuit given below is 