Question

The total number of hydrogen atoms in product A and product B is ______.

Answer 1

Correct Answer: 10

Reaction Analysis:

The reaction proceeds in the following stages:

1. Ethyl bromide (\( \text{CH}_3\text{CH}_2\text{Br} \)) reacts with sodium hydroxide (\( \text{NaOH} \)).
2. The initial reaction produces ethanol (\( \text{C}_2\text{H}_5\text{OH} \)) and subsequently ethene (\( \text{CH}_2 = \text{CH}_2 \)).
3. In the second stage, water (\( \text{H}_2\text{O} \)) undergoes addition to the double bond of ethene, yielding ethanol (\( \text{CH}_3\text{CH}_2\text{OH} \)).

Hydrogen Atom Count:

We will now tally the hydrogen atoms in the reactants (A) and products (B):

• Reactant A: \( \text{CH}_3\text{CH}_2\text{Br} \) (ethyl bromide) contains \( 3 + 2 = 5 \) hydrogen atoms.
• Reactant B: \( \text{NaOH} \) (sodium hydroxide) contains 0 hydrogen atoms.
• Product 1: \( \text{CH}_2 = \text{CH}_2 \) (ethene) contains \( 2 + 2 = 4 \) hydrogen atoms.
• Product 2: \( \text{CH}_3\text{CH}_2\text{OH} \) (ethanol) contains \( 3 + 2 + 1 = 6 \) hydrogen atoms.

Total Hydrogen Atom Count:

The sum of hydrogen atoms from reactants and products is \( 5 \) (from \( \text{CH}_3\text{CH}_2\text{Br} \)) \( + 6 \) (from \( \text{CH}_3\text{CH}_2\text{OH} \)) = 10 hydrogen atoms.