Question:medium

The total number of compounds having Bond order 2 among the following are: F2, N2, Ne2, O2, Li2, Be2, C2

Updated On: Feb 24, 2026
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Correct Answer: 2

Solution and Explanation

To determine the number of compounds with a bond order of 2, we calculate the bond order for each given molecule using the formula: Bond Order = (Number of electrons in bonding molecular orbitals - Number of electrons in antibonding molecular orbitals)/2.
  • F2: The electronic configuration is (σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(π2p)4(σ2p)2. Bond order = (10-8)/2 = 1.
  • N2: The electronic configuration is (σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(π2p)4(σ2p)2. Bond order = (10-2)/2 = 3.
  • Ne2: The electronic configuration is (σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(π2p)4(σ2p)4(π*2p)4. Bond order = (10-10)/2 = 0.
  • O2: The electronic configuration is (σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(π2p)4(σ2p)2(π*2p)2. Bond order = (10-6)/2 = 2.
  • Li2: The electronic configuration is (σ1s)2(σ*1s)2(σ2s)2. Bond order = (4-2)/2 = 1.
  • Be2: The electronic configuration is (σ1s)2(σ*1s)2(σ2s)2(σ*2s)2. Bond order = (4-4)/2 = 0.
  • C2: The electronic configuration is (σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(π2p)4. Bond order = (8-2)/2 = 3.
Compounds with bond order 2: O2.
The total number of compounds with bond order 2 is 1. The expected range is 2, but O2 is the only compound with bond order 2 from the list.
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