Question:medium
The total energy of a particle executing simple harmonic motion with 2 cm amplitude is 160 mJ. The force acting on the particle at a point where the ratio of the potential and kinetic energies of the particle becomes 1 : 15 is
The total energy of a particle executing simple harmonic motion with 2 cm amplitude is 160 mJ. The force acting on the particle at a point where the ratio of the potential and kinetic energies of the particle becomes 1 : 15 is
Show Hint
In SHM, force is always proportional to displacement: $F=kx$.
Updated On: Jun 22, 2026
- 16 N
- 12 N
- 8 N
- 4 N \bigskip
Show Solution
The Correct Option is C
Solution and Explanation
Was this answer helpful?
0
Top Questions on Simple Harmonic Motion
- A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is
- NEET (UG) - 2017
- Physics
- Simple Harmonic Motion
- For a simple pendulum, having time period T, the variation of kinetic energy (K.E.) with time (t) is represented by: ____.
- NEET (UG) - 2026
- Physics
- Simple Harmonic Motion
- The potential energy of a simple harmonic oscillator when the particle is half way to its end point is (where $ E $ is the total energy):
- AP EAPCET - 2026
- Physics
- Simple Harmonic Motion
- A particle executes simple harmonic motion according to the equation \( x(t) = A \sin^2(\alpha t) \). If the time period of the S.H.M is 0.2 s, then the value of \( \alpha \) (in units of rad/s) is:
- TS EAMCET - 2026
- Physics
- Simple Harmonic Motion
- Want to practice more? Try solving extra ecology questions todayView All Questions