Question:medium

A particle executes simple harmonic motion according to the equation \( x(t) = A \sin^2(\alpha t) \). If the time period of the S.H.M is 0.2 s, then the value of \( \alpha \) (in units of rad/s) is:

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\( \sin^2\theta = \frac{1 - \cos 2\theta}{2} \). The period of \( \cos(2\alpha t) \) is \( \pi/\alpha \), not \( 2\pi/\alpha \).
Updated On: May 12, 2026
  • \( 2\pi \)
  • \( 10\pi \)
  • \( 5\pi \)
  • \( 2.5\pi \)
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The Correct Option is C

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